15x^2+63=114x

Solution for 15x^2+63=114x equation:

15x^2+63=114x

We move all terms to the left:

15x^2+63-(114x)=0

a = 15; b = -114; c = +63;
Δ = b2-4ac
Δ = -1142-4·15·63
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-114)-96}{2*15}=\frac{18}{30}
=3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-114)+96}{2*15}=\frac{210}{30}
=7
$